help

i need help with this math problem. your answers will be rewarded.

log_2(log_16[log_3x])=-1

i need the answer and the work to be shown.|||not really sure how to interpret the log_3x part, but if you mean log base 3 of X, then it goes like this:

log_2(log_16[log_3x])=-1

log_16(log_3x)=0.5

log_3x=4

x=81

I hope that's right, otherwise I will feel very foolish :-)